syntak mencari division dengan java

ini adalah sintak programnya

import java.io.*;

class ar {

public static void main(String[] args) throws IOException {

String NPM, kode;

int hb, hb2, hb3, hb4, hb5, ar, ar2, ar3, ar4, ar5, n, k, nkey, nkey2, nkey3, nkey4, nkey5;

int record = 5832;

int max = 8331;

int fp = 11;

InputStreamReader j = new InputStreamReader(System.in);

BufferedReader m = new BufferedReader(j);

System.out.print("Soal\t:\nBuat 5 key dengan \nKey awal = NPM + Kode mata kuliah\nKey 2\t = Key awal + 3"

+ "\nKey 3\t = Key 2 + 11\nKey 4\t = Key 3 + 17\nKey 5\t = Key 4 + 23"+

"\n\nDengan diketahui :\n- Jumlah record\t= 5832\n- Faktor Muat\t= 0,7\n- Faktor Prima\t= 11");

System.out.print("\n\nMasukkan NPM : ");

NPM = m.readLine();

n = Integer.valueOf(NPM).intValue();

System.out.print("\nMasukkan kode MK : ");

kode = m.readLine();

k = Integer.valueOf(kode).intValue();

nkey = n + k;

hb = nkey / (max + fp);

ar = (nkey % 8342) + 1;

nkey2 = nkey + 3;

hb2 = nkey2 / (max + fp);

ar2 = (nkey2 % 8342) + 1;

nkey3 = nkey2 + 11;

hb3 = nkey3 / (max + fp);

ar3 = (nkey3 % 8342) + 1;

nkey4 = nkey3 + 17;

hb4 = nkey4 / (max + fp);

ar4 = (nkey4 % 8342) + 1;

nkey5 = nkey4 + 23;

hb5 = nkey5 / (max + fp);

ar5 = (nkey5 % 8342) + 1;

System.out.print("\nKey awal\n");

System.out.print("Hasil Bagi\t= " + hb);

System.out.print("\nAlamat Relatif = " + ar);

System.out.print("\n\nKey kedua\n");

System.out.print("Hasil Bagi\t= " + hb2);

System.out.print("\nAlamat Relatif = " + ar2);

System.out.print("\n\nKey ketiga\n");

System.out.print("Hasil Bagi\t= " + hb3);

System.out.print("\nAlamat Relatif = " + ar3);

System.out.print("\n\nKey keempat\n");

System.out.print("Hasil Bagi\t= " + hb4);

System.out.print("\nAlamat Relatif = " + ar4);

System.out.print("\n\nKey kelima\n");

System.out.print("Hasil Bagi\t= " + hb5);

System.out.print("\nAlamat Relatif = " + ar5);

}

}